![]() If you do not understand what is causing this behavior, please contact us here. If you promise to stop (by clicking the Agree button below), we'll unblock your connection for now, but we will immediately re-block it if we detect additional bad behavior. Overusing our search engine with a very large number of searches in a very short amount of time.Using a badly configured (or badly written) browser add-on for blocking content.Running a "scraper" or "downloader" program that either does not identify itself or uses fake headers to elude detection.Using a script or add-on that scans GameFAQs for box and screen images (such as an emulator front-end), while overloading our search engine.There is no official GameFAQs app, and we do not support nor have any contact with the makers of these unofficial apps. Continued use of these apps may cause your IP to be blocked indefinitely. This triggers our anti-spambot measures, which are designed to stop automated systems from flooding the site with traffic. Some unofficial phone apps appear to be using GameFAQs as a back-end, but they do not behave like a real web browser does.Using GameFAQs regularly with these browsers can cause temporary and even permanent IP blocks due to these additional requests. If you are using Maxthon or Brave as a browser, or have installed the Ghostery add-on, you should know that these programs send extra traffic to our servers for every page on the site that you browse.The most common causes of this issue are: This is simply the number of unsigned integers 2^64 = 18446744073709551616, since each seed is a 64-bit integer.Your IP address has been temporarily blocked due to a large number of HTTP requests. Let C be the number of cards available, and D be the starting deck size, then the answer is (applying multiplication rule): P(same) = 1/22 * (1/C)^(D) Apply the inverse rule again to find the probability that at least one seed exists: P(one seed) = 1 - (1 - P(same)))^NĬorollary 1: The inverse 1 / P(same) is the amount of seeds you would have to try to find at least one success on average (expectation of geometric variable).Ĭorollary 2: By multiplying the probability P(same) with the number of seeds N and the number of cards C (each card is independent), you get the expected total number of perfect seeds.Īll cards need to be the exact same specific card. Thus the probability that no seed exists is (1 - P(same))^N. For this to happen N times, multiply itself by N by applying the Multiplication Rule N times. The probability that all cards are not the same is 1 - P(same) by applying the Inverse Rule. Then, combine the two steps with the following proof: Figure out what the probability is that all cards are the same and the relic is pandora, denoted P(same). ![]() That means the seed searching program must have searched a substantial fraction (1% or so) of the total seed space to find all the perfect seeds it found, showing the power of a GPU (and why 64 or even 80 bit keys are now insecure in crypto) Reasoning | Character | Perfect chance | Number of seeds | Trials | The following table details the chance there is at least one seed, the expected amount of them that exist, and the number of seeds you would have to try to find one by pure chance: +-+-+-+-+ ![]() ![]() The cause is the fact that adding one more card to the starting deck makes it 71 or 72 times less likely for a seed to succeed.įor the Silent, there's about a 22.7% chance any specific card has a perfect seed. (In fact, I believe the algorithm has already found most of the Defect and Watcher seeds, and has found a few of the Ironclad ones). For the Ironclad, Defect, and Watcher one very likely exists for every card. ![]()
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |